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UMME AIMAN Grade: 12
        The speed of a projectile when it is at its greatest height is (2/5)raised to the power 1/2 times its speed at half the maximum height.The angle of projection is?
7 years ago

Answers : (1)

Chetan Mandayam Nayakar
312 Points
										

ucos(theta) = (√(2/5))(√((u2cos2(theta)+(u2sin2(theta)-(2gu2sin2(theta)/4g))))


thus, cos(theta)= sqrt((1+(cos(theta))^2)/5)


thus theta = 60 degrees

6 years ago
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