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A srone tied to a string of length L is whirled in a vertical circle with the other end of the string at the centre. At a certain instant of time, the stone is in the lowest position , and has a speed u. The magnitude of the change in its velocity as it reaches a position where the sting is horizontal is :
a) root (u^2 - 2gL)
b) root (2gL)
c) root (u^2 - gL)
d) root (2(u^2 - gL))
please help by answering this Q and the method to do this Question
applying energy conservation
1/2mu^2=mgl+1/2mv^2
we get v=root(u^2-2gl)
in vector form we can express as v vector=root(u^2-2gl)j and u vector =ui
difference is v-u =root(u^2+v^2)=root(2(u^2-gl))
Can some1 explain this more clearly !
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