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sumit kumar Grade: 12
        

Plz solve hc verma  , vol 1 –Pg 10 No. 19…

8 years ago

Answers : (1)

askiitian expert akshay singh
8 Points
										

hi,


let me make clear inregral is just summation so its not gonna effect dimensions of term inside integral sign. Integral of dx/ a2-x2   is 1/a( sin-1 x/a),dimension of dx is L,and that of a2-x2 is also L therefore dx/ a2-x2 is dimensionless and on the R.H.S 1/a has L-1 dimension and sin-1 term is dimensionless,therefore L.H.S is dimensionless and R.H.S is L-1 ,so The eq. is not correct dimensionally.

8 years ago
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