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Jayesh Arun Kadam Grade: 12
        

A particle rest on the top of a smooth hemisphere of radius r. It is imparted a horizontal velocity of √(ngr) (root). The angle made by radius vector joining the particle with the verticle, at the instant, the particle looses contact with sphere is Θ.


Find cosΘ.

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

      applying energy conservatin


1/2mu^2 +mgr(1-cosq)=1/2mv^2   eq-1


       u^2=ngr           (given)


and we have


                  mgcosq-N=(mv^2)/r    eq-2


  here N  normal reaction ,at this point N is zero


on solving we get


                     cosq=(n+2)/4

6 years ago
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