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A ball starts falling with zero initial velocity on a smooth inclined plane forming an angle alpha with the horizontal. Having fallen the distance h, the ball rebounds elastically off the inclined plane. At what distance from the impact point will the ball rebound for the second time?
since the collision is elastic velocity along the common normal interchanges and along the incline remains same.
theresfore velocity along incline= and along normal =
so distance along the incline=............1
this gives t as 2v/g where v=
substitute this in 1 to get the answer
the answer should be
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