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`        a ball is thrown vertically upwards with a velocity 'u' from the balloon  descending with a constant velocity 'v'.. the ball will pass by the  balloon after what time?`
7 years ago

110 Points
```										the relative velocity of ball wrt ground is (u-v)
it will go up a distance of (u-v)^2/2*g
and then come to the same height after a time period of (u-v)/g
during this time interval the balloon would be at -(u-v)v/g
now take the rest of the time to be t
during this time the ball comes down a distance of (u-v)v/g + vt
put this distnace into -gt^2/2
a quadriatic equation in t would come solve it for a positve t
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7 years ago
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