MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
Sneha Kanekar Grade: 12
        

an object of mass 5kg is projected with v=20m/s at angle of 60 wit d horizontal .at highest point of its path d projectile explodes and breaks into 2 fragments of mass 1kg and 4kg.they separate horizontally.the explosion releases internal energy such tat K.E of system is doubled.calculate separation between 2 fragments wen dey reach the ground

6 years ago

Answers : (1)

Aditya Nijampurkar
16 Points
										

 projectile motion


velocity at highest point before explosion=20cos 60°=10 m/s..

before explosion, energy=1 2X5X102 J

after collision, energy=5X102 J

now vel of 4 kg part=V and 1 kg part=v

so, 5X10=4V-v

1 24V2+1 2v2=500

now the second case will be when we ll consider the case wer 1 kg mass flies in direction of projectile motion b4 explosion...

i e we ll write 5X10=v-4V

next time to fall is time for free fall ie half the time of flight for the original projectile..

and distance between the two will be (V+v)t
6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: R 2,600
  • View Details
  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details