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Vishrant Vasavada Grade: 11
        

Particle is dropped from the height of 20 m from the horizontal ground. There is wind blowing due to which horizontal acc. of the particle becomes 6 m/s/s. Find the horizontal disp. of the particle till it reaches the ground.

7 years ago

Answers : (1)

AskiitiansExpert Abhinav Batra
25 Points
										

Height = 20 m


so by using the following equation for motion in vertical direction


we know g=10 and u=0 and s= 20


s= ut + 1/2 gt^2


20=1/2*10*t^2; (as u=0)


thus t= 2 sec


Hence the particle will reach the ground after 2 sec


 


a(in horizontal direction)=6


Again usng the same equation but now for horizontal motion of particle


s=ut + 1/2 at^2


we know t=2 and u=0


so s=1/2*6*4


s=12 m


So horizontal displACEMENT OF PARTICLE =2M


 


ALL THE BEST!

7 years ago
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