A particle is projected vertically upwards from a point A on the ground. It takes time t1 to reach a point B but it still continues to move up. It takes further time t2 to reach ground from point B. Then height of B from gound is what? (Ans: 1/2 g t1 t2)

Question

Anshuman Singh · Answer

LET THE HIGHEST POINT WHERE THE BALL REACHES AFTER POINT B be C. TIME TAKEN BY BALL TO REACH B IS t1 AND TIME TAKEN TO (REACH C FROM B+C to A) is =t2. We know that Time taken to reach max.height is = time taken to reach ground from that point. Therefore ,Total time of flight=(t1+t2) Time taken to reach C from A=(t1+t2)÷2 From A to C -; v=u+(-g)t 0=u-g (t1+t2)÷2u u=(gt1+gt2)÷2 using, s=ut+0.5at^2 till bNow,by putting value of u,a=-g,t=t1we get-AB=(0.5)(g)(t1)(t2)

Samuel Garry · Answer

Time taken for the particle to reach highest point is t1+t22t1+t22 (v=u−gt)(v=u−gt) Therefore initial velocity=u=g(t1+t22)=u=g(t1+t22) Therefore heigh of B from ground is h=ut+12h=ut+12at2at2 h=ut1−12h=ut1−12gt12gt12 =g(t1+t22)=g(t1+t22)t1−12t1−12gt21gt12 h=12h=12gt1t2

Rishi Sharma · Answer

Dear Student,
Please find below the solution to your problem.

Time taken for the particle to reach highest point is t1+t22t1+t22
(v=u−gt)(v=u−gt)
Therefore initial velocity=u=g(t1+t22)=u=g(t1+t22)
Therefore heigh of B from ground is
h=ut+12h=ut+12at2at2
h=ut1−12h=ut1−12gt12gt12
=g(t1+t22)=g(t1+t22)t1−12t1−12gt21gt12
h=12h=12gt1t2

Thanks and Regards

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

A particle is projected vertically upwards from a point A on the ground. It takes time t1 to reach a point B but it still continues to move up. It takes further time t2 to reach ground from point B. Then height of B from gound is what? (Ans: 1/2 g t1 t2)

A particle is projected vertically upwards from a point A on the ground. It takes time t1 to reach a point B but it still continues to move up. It takes further time t2 to reach ground from point B. Then height of B from gound is what? (Ans: 1/2 g t1 t2)

3 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

IIT JEE Courses

One Year IIT Programme

Two Year IIT Programme

Crash Course

NEET Courses

One Year NEET Programme

Two Year NEET Programme

One to One

School Board

Live Online classes

Class 11 & 12

Class 9 & 10

Class 6, 7 & 8

Test Series

JEE test series

NEET test series

C.B.S.E test series

Complete Self Study Packages

FULL COURSE

For class 12th

For class 11th

A particle is projected vertically upwards from a point A on the ground. It takes time t1 to reach a point B but it still continues to move up. It takes further time t2 to reach ground from point B. Then height of B from gound is what? (Ans: 1/2 g t1 t2)

A particle is projected vertically upwards from a point A on the ground. It takes time t1 to reach a point B but it still continues to move up. It takes further time t2 to reach ground from point B. Then height of B from gound is what? (Ans: 1/2 g t1 t2)

3 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship