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Subhajit Chakraborty Grade: 12
        

Mass of a pendulam is 10-2 kg. It is lifted to 5×10-2 m and released. At the lowest point of its path an extra mass of 10-3  kg  is attached with the pendulam. Find the height travelled by the pendulam At the opposite side.

7 years ago

Answers : (1)

Askiitians Expert Soumyajit IIT-Kharagpur
28 Points
										

Dear Subhajit,


Ans:- The velocity at the bottommost point is=√(2*10*0.05) m/s=1m/s


From the conservation of momentum we get the final velocity at the bottommost point after the extra mass is hanged is


=10-²*1/(10-²+10-³)


=0.91 m/s


Let the max height is =H m


Then H=0.91²/(2*10)


=4.1×10-² m  


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Regards,


Askiitians Experts


SOUMYAJIT IIT_KHARAGPUR

7 years ago
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