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the force acting on moving charge particle in a uniform magnetic field is (a) normal to magnetic field (b) at 45 degree from the magnetic field (c) parallel to the magnetic field

the force acting on moving charge particle in a uniform magnetic field is 
(a) normal to magnetic field
(b) at 45 degree from the magnetic field
(c) parallel to the magnetic field

Grade:12

1 Answers

Nirmal Singh.
askIITians Faculty 44 Points
9 years ago
(i) Let us consider Charge of particle is q and velocity is v then if Charge will move in Magnetic field B normal to the magnetic field then theta = 90

F = qv B Sintheta

F = qvBSin90
F = qvB Newton

(II)Let us consider Charge of particle is q and velocity is v then if Charge will move in Magnetic field B normal to the magnetic field then theta = 45

F = qv B Sintheta

F = qvBSin45
F = qvB / sqrt (2) Newton

(iii)Let us consider Charge of particle is q and velocity is v then if Charge will move in Magnetic field B normal to the magnetic field then theta = 0

F = qv B Sintheta

F = qvBSin0
F = 0 Newton

Regrads.

Nirmal SIngh
Askiitians Faculty

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