0

Guest

Courses New

Q. Two identical charged particle A and B initially at rest are accelerated by a common potential difference V. They enter into a transverse magnetic field B and describes a circular path of radii r1 and r2 respectively then what is their Mass ratio?

Q. Two identical charged particle A and B initially at rest are accelerated by a common potential difference V. They enter into a transverse magnetic field B and describes a circular path of radii r1 and r2 respectively then what is their Mass ratio?

Grade:12

1 Answers

Vikas TU
14149 Points
6 years ago
As the particles start from rest, kinetic energy would be the work done on the particle by V, lets assume the charge on the particle is q, then
(1/2)m1v12 = qV  and
(1/2)m2v22 = qV
 
  • m1v12 = m2v22   ----- (1)
 
Magnetic force on each particle = Centripetal force on the particle
  •  m1v12 /R1 = qBv1  
  • v1 = qBR1/m1
Similarly,
  •   v2 = qBR2/m2
  • When we put the value in equ 1 we get,
  • m1 (qBR1/m1)2 = m2 (qBR2/m2)2
  • R12/m1 =  R22/m2
  • m1/m2 =  R12/R22

Think You Can Provide A Better Answer ?

Other Related Questions on Magnetism

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More