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n electron is accelerated from rest through a potential difference of 400 V. The electron then enters a uniform magnetic field that is perpendicular to the direction of electrons. The radius of the circular path experienced by the electron is 10 cm. The angular speed of electrons, in radians/sec, is Given data: Charge of electron = 1.6 × 10−19 C; Mass of electron = 9.1 × 10−31 Kg(A) 1.18 × 107 (B) 1.18 × 108 (C) 2.18 × 107 (D) 2.18 × 108

n electron is accelerated from rest through a potential difference of 400 V. The electron then enters a uniform magnetic field that is perpendicular to the direction of electrons. The radius of the circular path experienced by the electron is 10 cm. The angular speed of electrons, in radians/sec, is Given data: Charge of electron = 1.6 × 10−19 C; Mass of electron = 9.1 × 10−31 Kg(A) 1.18 × 107 (B) 1.18 × 108 (C) 2.18 × 107 (D) 2.18 × 108

Grade:12th pass

1 Answers

Vikas TU
14149 Points
6 years ago
Dear Student,
From the energy Conservation,
KE = PE
1/2mv2=qV
=>v=√(2qV/m)
w=v/R
=1.18x108
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
 

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