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Figure shows a circular wire loop of radius 0.5 carriying current i placed in a perpendicular magnetic field 1/3. (a) Consider a small part dl of the wire. The force on this part of wire exerted by the magnetic field in the radially outward direction is idl/N. Find N.

Figure shows a circular wire loop of radius 0.5 carriying current i placed in a perpendicular magnetic field 1/3. (a) Consider a small part dl of the wire. The force on this part of wire exerted by the magnetic field in the radially outward direction is idl/N. Find N.

Grade:12

1 Answers

ROSHAN MUJEEB
askIITians Faculty 833 Points
3 years ago
Fdl=i×dl×B towards centre. (By cross product rule)
(b) Let the length of subtends an small angle of 2θ at the centre
Here,
2Tsinθ=i×dl×B
2Tθ=i×a×2θ×B [As θ→0,sinθ≈0]
T=i×a×B
T=a i B
Force of compression on the wire =iaB

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