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hi ,
velocity of first one, v1= (2*q*V /m) 1/2
for first particle velocity parallel to the field v 1z = v1 cos y
perpendicular to field , v1x = v1 sin y
speed of the second particle so that the particles meet at minimumtime will be equal to the parallel component of v1
so v2 = v1 cos y
time interval after they meet will be the time taken in one ratation of particle 1,
t = 2*pi* r / v1 siny
where r = m v1 sin y /q B
hence t = 2 m pi / q B
distance travelled by the second one durin the interval
d = v2 * t
= 2 m* v1 cos y* pi / q* B
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