Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: R

There are no items in this cart.
Continue Shopping
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details
Get extra R 700 off


 How many neutral points on a horizontal board are there when a manget is held vertically on the board

6 years ago


Answers : (2)


Dear deepak,

If earth's magnetic field is considered as "B" ,then it has two components along horizontal and vertical.But while determining null or neutral points of a bar magnet only horizontal component of magnetic field is taken into consideration but not vertical component of magnetic field.

The reason Earth's magnetic field has a horizontal and vertical component is because it is oriented at angle with regard to the bar magnet in most places on Earth. Generally, you choose the reference frame to be that of the plane of the lab bar magnet. Of course you can also do it the other way and say that the lab bar magnet has a horizontal and vertical component while Earth magnet is purely in one direction but that makes things more complicated.

In the UK, the field lines lie about 70 degrees with regard to the horizontal. So when you conduct an experiment to measure the Earth's magnetic field by finding the null points between bar magnet and Earth magnet, you are only finding the horizontal component of the Earth's magnetic field.

We are all IITians and here to help you in your IIT JEE preparation.

All the best.

 If you like this answer please approve it....

win exciting gifts by answering the questions on Discussion Forum


Sagar Singh

B.Tech IIT Delhi

6 years ago


6 years ago

Post Your Answer

Other Related Questions on Magnetism

The S.I unit of magnetic field induction?
Weber/m 2
SAIMANIKANTA one year ago
Weber/m 2 is the unit of the magnetic field induction. And Electromagnetic induction is the production of an electromotive force across a conductor exposed to time varying magnetic fields....
SAI SANDY 10 months ago
Dear Kajal, The S.I. unit of Magnetic field induction is Weber/Meter 2 .And it from the formula of magnetid field induction.
SAI SARDAR 10 months ago
what is tension in the ring of radius r carrying current i and placed in external magnetic field b.also give a hint how to solve this
Tension in the ring is equal to irb where I is the current b is the magnetic field and radius of the ring is r gewt this take a element of a ring and equate the forces...of you son...
Himanshu 11 months ago
what are the conditions for applying ampere circuital law?
Follow the steps given to apply Ampere’s circuital law: Step 1: Consider a symmetrical closed path such that it encloses direct current I once. This is Amperian path. Step 2: Consider...
dolly bhatia 4 months ago
Some points get remained: The integeral integeation above equation means that scalar product B . dl is to be integrated around the closed loop known as Amperian loop whose beginning and end ...
Vikas TU 4 months ago
Ampere's circuital law in magnetism is analogous to gauss's law in electrostatics This law is also used to calculate the magnetic field due to any given current distribution This law states ...
Vikas TU 4 months ago
Three particles start moving from the origin at the same time. Particle 1goes in x-direction with velocity v1 and 2nd in y-direction with v2. Particle 3 goes along line y=x and velocity v3....
Find the distance at any time taken as cinstant suppose take t = 1 s and then we can caluclate velocity later on. . For x – axis, x = V1 For y-axis y = V2 for y=x, x0 = V3cos45 and y0 =...
Vikas TU 2 months ago
how can we develop the equtaion of potentila drop in the potential meter
Potential drop is given as: x = V/l and also V1/V2 = l1/l2 l would be the length measured where potentiometer reading shows zero.
Vikas TU 2 days ago
3 point charges lie along a straight line with positive charge at the centre and negetive at the ends all are ‘a’ distance apart from each other. The energy needed to exchange the position...
Let the charges be -q, +q and -q. Distance between two charges = a Energy of the system putting the values we get U initial = Final energy of the system, U final = Therefore, work required...
Raman Mishra one month ago
View all Questions »

  • Complete Physics Course - Class 12
  • OFFERED PRICE: R 2,600
  • View Details
Get extra R 650 off

  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details

Get extra R 700 off

More Questions On Magnetism

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!!
Click Here for details