MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
sanket sit Grade: 11
        

At Calcutta, here the vertical component of the earth's field is 0.26(dyne per unit pole) it is found that a mass of 10mg placed 10cm from the axel of a dip-needle keeps it horizontal.Find the magnetic moment of the dip-needle( acceleration due to gravity is 1000cm/sec2)

7 years ago

Answers : (1)

Askiitians Expert Soumyajit IIT-Kharagpur
28 Points
										

Dear Sanket,


Ans:- Let the magnetic moment is M unit.


Then the moment about the axle of the dip needle is MV where V=0.26 dyne/pole


The moment given by the point mass=mgx where x=10 cm


Hence we get,


MV=mgx


M=mgx/V


  =(10*10-³ *10³ *10)/0.26=384.6 unit(ans)


 


Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.



All the best Sanket !!!


 



Regards,


Askiitians Experts


SOUMYAJIT IIT_KHARAGPUR

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: R 2,600
  • View Details
Get extra R 520 off
USE CODE: CART20
  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details
Get extra R 560 off
USE CODE: CART20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details