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aakash diwedi Grade:
        

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A metal rod 1.5 m long rotates about its one end in a vertical plane at right angles to the magnetic meridian. If the frequency of rotation is 20 rev/s. Find the emf induced between the ends of rod.


                             BH = 0.32 ´ 10-4T: Horizontal component of earth’s magnetic field.


7 years ago

Answers : (1)

Shane Macguire
30 Points
										

Dear aakash,


The given information is as follows:


Length of rod     = 1.5 mt.


                             Frequency of rotation    = 20 rev/sec.


                             BH = 0.32 * 10-4 T


                             Angular velocity of rod = 20 * 2∏ rad/sec.


                             emf induced = B*dA/dt = 0.32*10-4 *20*∏*(1.5)2.


       Therefore horizontal component of the earth's magnetic feild is  =  4.5 * 10-3 V.


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7 years ago
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