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Vikas TU Grade: 12th Pass
        An aeroplane lefts 30 minute later than it's shedule time and in order to reach its destination 1500 km away in time. It had to increase its speed by 250 km/hr. from its usual speed. Determine its usual time.
5 years ago

Answers : (1)

Sudheesh Singanamalla
114 Points
										

Let the usual speed of the plane be 'x' hours


Time taken to cover 1500km with usual speed = 1500/x hrs


time taken to cover 1500km with speed of (x+250) = 1500/(x+250) hrs


1500/x = 1500/(x+250) + 1/2


1500/x - 1500/(x+250) = 1/2


1500x + 1500*250 - 1500x / (x*(x+250)) = 1/2


1500*250 / x2+250x = 1/2


750000 = x2 + 250x


x2+250x - 750000 = 0


x2 + 1000x - 750x - 750000 = 0


x ( x+1000) - 750 (x+1000) =0


(x+1000)(x-750) = 0


which means x = -1000 , which is not possible , as speed cannot be negative


or x = 750


so the usual speed of the plane is 750 kmph


usual time = distance / speed = 1500 / 750 = 150/75 = 2 hours !


 


Please approve !

5 years ago
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