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`        An aeroplane lefts 30 minute later than it's shedule time and in order to reach its destination 1500 km away in time. It had to increase its speed by 250 km/hr. from its usual speed. Determine its usual time.`
6 years ago

Sudheesh Singanamalla
114 Points
```										Let the usual speed of the plane be 'x' hours
Time taken to cover 1500km with usual speed = 1500/x hrs
time taken to cover 1500km with speed of (x+250) = 1500/(x+250) hrs
1500/x = 1500/(x+250) + 1/2
1500/x - 1500/(x+250) = 1/2
1500x + 1500*250 - 1500x / (x*(x+250)) = 1/2
1500*250 / x2+250x = 1/2
750000 = x2 + 250x
x2+250x - 750000 = 0
x2 + 1000x - 750x - 750000 = 0
x ( x+1000) - 750 (x+1000) =0
(x+1000)(x-750) = 0
which means x = -1000 , which is not possible , as speed cannot be negative
or x = 750
so the usual speed of the plane is 750 kmph
usual time = distance / speed = 1500 / 750 = 150/75 = 2 hours !

```
6 years ago
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