Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        In a triangle if the lenght of the sides are a,b,c.then the given condition is a2+b2+c2=ab+bc+ca.then the triangle formed is a]right angled b]obtuse angled c]acute angled........[I want to know  about the angle of the triangle ...so please help me to solve this problem]
```
6 years ago

510 Points
```										a2+b2+c2 = ab+bc+ac               (given)
cosA = b2+c2-a2/2bc
2bccosA = b2+c2-a2           ...........1
2accosB = a2+c2-b2             ..........2
2abcosC = a2+b2-c2            .........3
2(abcosC+bccosA+accosB) = a2+b2+c2       ........4
a2+b2+c2 = ab+bc+ac              (given)
so , 2(abcosC+bccosA+accosB) = ab+bc+ac
2ab(cosC-1/2) + 2bc(cosA-1/2) + 2ac(cosB-1/2) = 0
from this eq , cosC = cosA = cosB = 1/2
A=B=C = Pi/3
so the triangle is equilateral , acute angled triangle...
approve if u like my ans
```
6 years ago
4 Points
```										though this isnt the exact solution but if you are looking for answer directly
the above condition satisifies when a=b=c,so it can be equilateral corresponds to the answer acute angled
```
6 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Magical Mathematics[Interesting Approach]

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details
Get extra Rs. 3,180 off
USE CODE: CHEM20
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details
Get extra Rs. 3,180 off
USE CODE: CHEM20