Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A cone is cut half way through its axis and parallel to the base, the volumes of two portions are in the ratio?

6 years ago

510 Points

let vertex of cone is  A ...

after drawing the axis about which cone is to cut  , then we will see that there will be two similar triangles  ...

radius of base of upper half is r1 & radius of base is R , height of original cone is 2H then

by using similarity of triangles , r1/H = R/2H

r1 = R/2

area of upper half = 1/3 (pi) (r1)2H = 1/3(pi)(R2H/4)

area of lower half = area of cone - area of upper half

=1/3(pi)(R22H) - 1/3(pi)(R2H/4)

=1/3pi(7R2H/4)

ratio of two parts = upper half/lower half = 1/7

6 years ago
Sudheesh Singanamalla
114 Points

6 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Magical Mathematics[Interesting Approach]

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details