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pankaj gupta Grade: 12
        

1.if 1/5^3y=0.008,then find the value of 0.25^y

6 years ago

Answers : (2)

Aman Bansal
592 Points
										

DEAR PANKAJ,


if 5-3y= (2*10-1)3


=> 5-y = 2*10-1


=> 5^y = 1/2*10


=>5^y= (5)^1


=>y=1


0.25^y=0.25^1=0.25


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AMAN BANSAL

6 years ago
Fawz Naim
37 Points
										

Here it is given that   1/5^3y=0.008


=>1/5^3y=8/1000


=>5^3y=1000/8    (taking reciprocal on both sides)


5^3y=(10/2)^3


5^3y=5^3


as base on both the sides are equal then the powers will also be equal


=>3y=3


=>y=1   now 0.25^y=0.25^1=0.25

6 years ago
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