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∫xcosnxdx

∫xcosnxdx

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1 Answers

Y RAJYALAKSHMI
45 Points
9 years ago
let u = x ; v = cosnx
du = dx;  ∫v = sinnx/n
This is in the form of ∫uv = u∫v – ∫∫v.du
∫xcosnxdx = xsinnx.n – ∫sinnx/n dx
= xsinnx/n – ( – cosnx/n)/n = xsinnx /n + cosnx / n2

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