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Q . THE AREA ENCLOSED BETWEEN THE CURVES - y = ln ( x + e ) and x = ln ( 1/y ) AND X-AXIS.

Q . THE AREA ENCLOSED BETWEEN THE CURVES -
   y = ln ( x + e )  and  x = ln ( 1/y ) AND 
X-AXIS.
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

Grade:Select Grade

2 Answers

Jitender Singh IIT Delhi
askIITians Faculty 158 Points
9 years ago
Ans:
Hello Student,
Please find answer to your question below

y = ln(x+e)
Intersect x-axis at (1-e, 0) & y-axis at (0, 1)
y = e^{-x}
Intersect y-axis at (0, 1).
Area A b/w two curves is:
A = \int_{1-e}^{0}ln(x+e)dx + \int_{0}^{\infty }e^{-x}dx
A = \int_{1-e}^{0}ln(x+e)dx + 1
A = [eln(x+e)-x]_{1-e}^{0} + 1
A = [e-(-(1-e))] + 1
A =2
Bharat Makkar
34 Points
9 years ago
thanks sir......and happy diwali.......

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