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please help anyone............jitendra sir where are you please help ….....

please help anyone............jitendra sir where are you please help ….....

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Grade:12

2 Answers

Jitender Singh IIT Delhi
askIITians Faculty 158 Points
9 years ago
Ans:
Hello Student,
Please find answer to your question below

log_{sinx}tanx >= 0
sinx should be b/w 0 & 1 (with both excluded)
\Rightarrow 0<x<\frac{\pi }{2}
log_{sinx}tanx >= log_{sinx}1
Since base(sinx) is less than 1. So when we cancel it out, inequality sign will change
tanx =< 1
\Rightarrow 0 =< x =< \frac{\pi }{4}
Intesection of both solution is
0 < x =< \frac{\pi }{4}

milind
23 Points
9 years ago
jitendra sir in third step .inequality sign changes why ? /............ thanks for your help ….…....
 

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