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integ 0 to π [sin ¹°°x.cos ??x] dx
let I =integral of 0 to p sin ¹°°xcos x dx I =integral of 0 to p sin ¹°°(p-x)cos(p-x )dx =-integral of 0 to p sin ¹°°xcos x dx = -I 2I=0 I=0Thanks & RegardsParvez AliaskIITians FacultyBtechISM Dhanbad
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