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I am not able to get that is it expansion or differentiaition

I am not able to get that is it expansion or differentiaition

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Grade:11

1 Answers

Vikas TU
14149 Points
6 years ago
Dear Student,
The question is asking to find limit of the given function. We will apply L hospital rule here i.e. we will differentiate numerator and denominator.
For differentiating the integral we will use theorem, diff of integral f(x).g(x) = f(g(x))∗g(x)′−f(h(x))∗h(x)′ .
So the given limit=lim x->0 (x*ln(1+x))/((x^4+4)*3x^2)
=lim x->0 1/3 * ln(1+x) /(x(x^4 +4))
Now putting value of x as 0,we get
Ans=1/12. So option (2) 1/12 is the correct answer.
The question is asking to find limit of the given function. We will apply L hospital rule here i.e. we will differentiate numerator and denominator.
For differentiating the integral we will use theorem, diff of integral f(x).g(x) = f(g(x))∗g(x)′−f(h(x))∗h(x)′ .
So the given limit=lim x->0 (x*ln(1+x))/((x^4+4)*3x^2)
=lim x->0 1/3 * ln(1+x) /(x(x^4 +4))
Now putting value of x as 0,we get
Ans=1/12. So option (2) 1/12 is the correct answer.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)

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