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hrithik krrish Grade: 11
        

integral of tanx/(sec x+cos x)?

7 years ago

Answers : (1)

Askiitians Expert Soumyajit IIT-Kharagpur
28 Points
										

Dear Hrithik Krrish,


Ans:- ∫tanx dx/(secx+cosx)


=∫sinx dx/(1+cos²x)


put cosx=z  So sinx dx = -dz


= -∫ dz/(1+z²)


= - tan¨¹z +c


= -tan¨¹(cosx) +c


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Askiitians Experts
Soumyajit Das IIT Kharagpur

7 years ago
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