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tejas sanjay akole Grade: 12
        

∫1/(1+x^3)


 

7 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

 1+x^3 =(1+x)(1+x^2-x)


  now expression becomes


   dx/(x+1)(x^2+1-x)


  applying partial fraction


   1/3logx+1 -1/6log(x^2-x+1) +[taninverse{2x-1/(3^1/2)}]/(3^1/2)


 


 

6 years ago
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