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∫1/(1+x^3)
1+x^3 =(1+x)(1+x^2-x)
now expression becomes
dx/(x+1)(x^2+1-x)
applying partial fraction
1/3logx+1 -1/6log(x^2-x+1) +[taninverse{2x-1/(3^1/2)}]/(3^1/2)
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