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`        the integral of ∫(1/lnx)dx is.......its 1 divided by natural log of x w.r.t. dx`
7 years ago

147 Points
```										Dear kshitij
you can find the solution of these type of integral in terms of infinite series
I=∫(1/lnx)dx
let lnx =t
or x= et
dx =etdt
I =∫(1/t) etdt
=∫(1/t)[1+t+t2/2! + t3/3! +..........]dt
=∫[1/t +1+t/2!  + t2/3! +..........]dt
=lnt + t + t2/2*2!  + t3/3* 3! +.........
=ln(lnx) + lnx + (lnx)2/2*2!   + (lnx)3/3* 3! +.........
=ln(lnx) +  ∑(lnx)r/r*r!  where r varies from 1 to infinity
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```
7 years ago
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