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				   integral sin{lim(t tends to 0)(2x/pie)cot(inverse)(x/t*t)}
take limit from -pie/2 to pie/2


6 years ago

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										Ans:0$I = \int_{-\pi /2}^{\pi /2}sin(\lim_{t\rightarrow 0}\frac{2x}{\pi }.\cot ^{-1}\frac{x}{t^{2}})dx$$I = \int_{-\pi /2}^{\pi /2}sin(\lim_{t\rightarrow 0}\frac{2x}{\pi }.0)dx$$I = \int_{-\pi /2}^{\pi /2}sin(0)dx$$I = \int_{-\pi /2}^{\pi /2}0dx = 0$Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

2 years ago

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