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`        solve ∫(dx/(x(xn +1))`
8 years ago

147 Points
```										Dear harshit agarwal
∫(dx/(x(xn +1))
multiply and devide by xn-1
integral will become
∫(xn-1dx/(xn(xn +1))
put xn=t
nxn-1dx=dt
now integral will become
1/n∫(dt/(t(t +1))
=(1/n)∫(dt/[(t +1/2)2-(1/2)2]
this can be easly solve
by using the formula for
∫(dt/[(t)2-(a)2]

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.  All the best harshit  Regards, Askiitians Experts Badiuddin

```
8 years ago
manoj jangra
8 Points
```										 just put
logx = y
1/xdx=dy
∫dy/eny  +1
from here you put take eny in numerator and put e-ny +1 = z
```
8 years ago
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