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(x2+x/(2x+1)1/2) dx


3 years ago

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 please find the attachment below


 


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3 years ago

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answer the question in image ….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….…....
 
 
write sec^3x as sec^x*secx and then integrate by using integration by parts ….................. take the first functions as secx and second functions as sec^x hence the integral will...
 
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Please it would be grateful if anybody could tell me the integration of xtan(x)dx
 
 
As it will result in the recursive equation and therefore it will be requried to convert into some special function.
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Vijay Mukati 6 months ago
 
I will try to provide it whenever I will be free. Thanks.
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Vijay Mukati 6 months ago
 
HIint. Please use the product rule for the integration here. Consider the x as 1 st term and tanx as second. Thanks.
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Vijay Mukati 6 months ago
Integrate within limits
 
 
Hello student, You have missed attaching the function which is to be integrated within the limits. Kindly check and post your question again so that we can get back to you with a meaningful...
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Latika Leekha 8 months ago
 
in which function comprising limit we have to integrate?
 
grenade 8 months ago
 
in which function comprising limit we have to integrate?
 
grenade 8 months ago
if A,B,C are mutually perpendicular prove that C×(A×B)=0 Also A,B,C are vectors
 
 
Dear Student, If A, B and C are mutually perpendicular then, A x B will be the vector perpendicular to both A and B i.e. C only. Now C x C = 0 because the cross product of two same vectors...
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Vijay Mukati 3 months ago
 
If A, B and C are mutually perpendicular then, A x B will be the vector perpendicular to both A and B i.e. C only. Now C x C = 0 because the cross product of two same vectors is zero....
 
Ankit Jaiswal 5 days ago
px 2 +qx+r/ax+b what will be the derivative of this question?
 
 
Derivate w.r.t x will be 2px + q -r/(ax 2 ).
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Vijay Mukati 6 months ago
FIND UNIT VECTORS PERPENDICULAR TO THE PLANE DETERMINED BY THE POINTS P(1,-1,2) , Q(2,0,-1) AND R(0,2,1).
 
 
The two vectors in the given plane is PQ & PR PQ = (2 – 1) i + (0 + 1) j + (-1 – 2)k = i + j – 3k PR = (0 – 1)i + (2 + 1) j + (1 – 2k = –i + 3j – k The vector perpendicular to PQ & PR is PQ ...
 
Y RAJYALAKSHMI one year ago
 
THANKS!!!!
 
Bharat Makkar one year ago
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