intregate from 0 to 3, (x^2+1)d[x] where [x] denotes greatest integer less than equal to x

2 years ago

Share

Answers : (1)

                                        

Hi Debadutta,


 


An integration where there is no variable of integration is not possible.


d[x] does not vary. It becomes a constant.


 


Regards,


Ashwin (IIT Madras).

2 years ago

Post Your Answer

More Questions On Integral Calculus

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
evaluate the following integral ∫ 1 / (sqrt(1 – x^2) ( 2 + 3 sin^-1 (x)) dx
 
 
Ans: Hello student, Please find the answer to your question below
  img
Jitender Singh 2 months ago
2 ∫ 0 (x 2 + 4) dx
 
 
Ans:- 2 ∫ 0 (x 2 +4)dx=[(x 2+1 /2+1 )+4x] --------- since (x n+1 /n+1) [(x 3 /3)+4x] 0 2 =[(2 3 /3)+8]=[(8/3)+3]=(8+24)/3=32/3
 
Anusha one month ago
 
Ans:- 2 ∫ 0 (x 2 +4)dx=[(x 2+1 /2+1 )+4x] --------- since (x n+1 /n+1) [(x 3 /3)+4x] 0 2 =[(2 3 /3)+8]=[(8/3)+3]=(8+24)/3=32/3
 
Anusha one month ago
integration root cos2A/sinA=
 
 
Ans: Hello student, Please find the answer to your question below
  img
Jitender Singh 2 months ago
If p(x) be a polynomial of degree 3 satisfying p(−1) = 10, p(1) = −6 and p(x) has maximum at x = −1 and p′(x) has minima at x = 1. Find the distance between the local maximum and local...
 
 
Hello Student, Let the polynomial be p(x)=ax^3 +bx^2 +cx+d p(-1)=–a + b – c + d = 10 p (1) = a + b + c + d = –6 p'(-1)=3a – 2b + c = 0 p''(1)= 6a + 2b = 0...
  img
Arun Kumar 4 months ago
if the tangent from a pt P on the circle x^2 + y^2 = 1 is perpendicular to tangent frm P to the circle x^2 + y^2 = 3, then locus of P is a circle of radius a)2 b)3 c)4 d)none of these
 
 
THe tangent to circle 1 : x.x1 + y.y1 = 1 from point(x1,y1) The tangent to circle 2 : x.x1 + y.y1 = 3 from point (x1,y1) These tangents are perpendicular. Hence, -x1/y1. -x1/y1 = -1 x1^2 /...
  img
bharat bajaj 8 months ago
 
thanku sir
 
vaanya 8 months ago
Integrate cosecx.sec3x
 
 
Hello Student, Thanks & Regards Arun Kumar Btech, IIT Delhi Askiitians Faculty
  img
Arun Kumar 4 months ago
View all Questions »