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                   indefinite integrals

3 years ago


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3 years ago

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We know that, tan(c-b) = (tan c – tan b)/(1+tan c * tan b), So, (1+tan c * tan b) = (tan c – tan b) / tan (c-b), Put c= x+a, b=x, (1+tanx * tan(x+a)) = (tan(x+a) – tan x) / tan(x+a-x)...
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udit maniyar 2 months ago
did u get this after simplification p/q 2 = (x – 1/x) + 3/(x – 1/x)
udit maniyar 2 months ago
if you feel the answer is right then approve it
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