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the value of integrand limit [0 to [x]] {x-[x]}dx (where [.] denotes greatest integer function.

3 years ago

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Answers : (2)

                                        

Arun Kumar
IIT Delhi
Askiitians Faculty
one year ago
                                        
x-[x] is periodic with period 1. therefore, ?0[x]x-[x] dx = [x]?01x-[x] dx =[x]/2
we can get integral of x-[x] within limits 0 and 1 using method of areas as ½.
Therefore the answer is [x]/2
one year ago

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∫e -( x*x) dx=?
 
 
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Y RAJYALAKSHMI 11 months ago
 
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Y RAJYALAKSHMI 11 months ago
 
Is this ∫e -( x 2 ) dx or ∫e -( x x ) dx pl. specify
 
Y RAJYALAKSHMI 11 months ago
∫x^4/(x^4-16)dx
 
 
simplify 2 nd term by partial fraction method Now above problem reduce to standard form and Do it yourself PLEASE APPROVE IF USEFUL
 
Aakash 20 days ago
5 ∫ 3 (2 – x) dx
 
 
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Miryala Gopalakrishna 10 months ago
 
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Anusha 10 months ago
File attached.
 
 
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Abhishek Kumar 4 months ago
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2016 years ago
 
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Akshay one month ago
 
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