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```                   the value of integrand limit [0 to [x]] {x-[x]}dx (where [.] denotes greatest integer function.
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3 years ago

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```                                        $\int_{0}^{[x]}x-[x]dx \\=>[x]^2/2-\int_{1}^{2}1dx-\int_{2}^{3}2dx-\int_{3}^{4}3dx..............depends\, value \,of\, [x]$Arun KumarIIT DelhiAskiitians Faculty
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one year ago
```                                        x-[x] is periodic with period 1. therefore, ?0[x]x-[x] dx = [x]?01x-[x] dx =[x]/2we can get integral of x-[x] within limits 0 and 1 using method of areas as ½.Therefore the answer is [x]/2
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one year ago

what do we mean by substitution in integration

A change in the variable of integration often reduces an integral to one of the fundamental integrals. The method in which you change the variable to some other variable is called the...

Integration by Substitution" (also called "u-substitution") is a method to find an integral , but only when it can be set up in a special way. When the integrand involves some trigonometric ...

 ng29 6 months ago
integral of sin with respect to x

Its −cosx(minus sign is also there).PLZ approve .

integral sinx = -cosx

 sri tanish 2 months ago

∫sinx.dx=-cosx+c

 Shantanu Singh 2 months ago
what is the antiderivative of sinx

anti derivative means integration and its value equals theta1 theta2 ∫sinx.dx = -cos(theta1-theta2) +c approve if useful

-COSX

 noogler 6 months ago
How to find common tangent of an ellipse with other ellipse?

Find the eq of tangent from ellipse 1, then put the value of tangent in ellipse 2 . from there u will get the value of m and(x,y)

F

what is adjugate the term is related to which theorem pl.xplain

adjoint of a matrix is also called adjugate i.e transpose of the co-factor matrix. You can refer to NCERT textbook. And which thoerem are you talking about? Cayley- Hamilton theorem???

 AUREA 5 months ago

I am talking about Jacobi theorem

I read Jacobi th in determinant

Find the range of maximum value M of 3^x + 5^x – 9^x – 25^x +15^x 0 5 3 9

Let 3 x = a, and 5 x = b. Let the given expression be S. We look at -S. Now -2S+2 = 2(a 2 +b 2 -ab-a-b)+2 = (a-1) 2 +(b-1) 2 +(a-b) 2 >=0. Hence S x = 5 x = 1 i.e. when x = 0.

 mycroft holmes 2 months ago

Small error, we have S Askiitians does not allow less than 100 characters. Hence this additional content!

 mycroft holmes 2 months ago
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