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USE CODE: EXAM25

```				   the value of integrand limit [0 to [x]] {x-[x]}dx (where [.] denotes greatest integer function.
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4 years ago

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```										$\int_{0}^{[x]}x-[x]dx \\=>[x]^2/2-\int_{1}^{2}1dx-\int_{2}^{3}2dx-\int_{3}^{4}3dx..............depends\, value \,of\, [x]$Arun KumarIIT DelhiAskiitians Faculty
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one year ago
```										x-[x] is periodic with period 1. therefore, ?0[x]x-[x] dx = [x]?01x-[x] dx =[x]/2we can get integral of x-[x] within limits 0 and 1 using method of areas as ½.Therefore the answer is [x]/2
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one year ago

what is integration? what is uses of integration: how to use integrations in real life?

Integration is an matematical Operation used to caluclate the area or volume of any given region/object.

 Vijay Mukati 4 months ago
i dont get topic of area under curvin askiitians what i do pleas suggest meeee

Refer to the book “PLAY WITH GRAPHS” arihant publication it has wide variety of graphing techniques and transformations and all possible graphs ranging from easiest to difficult.. once you...

 Himanshu 3 months ago
answer the question in image ….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….….…....

write sec^3x as sec^x*secx and then integrate by using integration by parts ….................. take the first functions as secx and second functions as sec^x hence the integral will...

 Himanshu 2 months ago
if points wid position vectors 60i+3j,40i-8j,ai-52j are collinear find a

Dear Student, You mark this points on coordinate axis having i and j directions perpendicular. Now since this points are collinear and thus the solve will be equal between them. You this...

 Vijay Mukati 2 months ago
Request you to solve the problem of Suarez root over 2 root over 2 for 24 times

hii, answer is 2 because =2 1/2 *2 1/4 *2 1/8 *2 1/16 .....*2 1/(2^24) =2 (1/2+1/4+1/8+1/16+1/32.......+1/ (2^24) =2^1 =2

 manmath 5 days ago

=2 1/2 *2 1/4 *2 1/8 *2 1/16 .....*2 1/(2^24) =2 (1/2+1/4+1/8+1/16+1/32.......+1/ (2^24) =2^1 =2 so, the answer is 2

 Rushil 2 months ago
What is the product of length of perpendicular drawn from any point on the hyperbola to its asymtotes. ..given only a and b...

Dear Student, For the hyperbola x 2 /a 2 – y 2 /b 2 = 1 , Te two asymptotes are given by x/a + y/b = 0 or x/a- y/b=0. We can rewrite these as bx + ay = 0 and bx – ay = 0...

 Vijay Mukati one month ago
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