Integration from 0 to infinity x2cosx / (xsinx)2

2 years ago

Share

Answers : (2)

                                        

=x2cos(x)/(xsin(x))2


=x2cos(x)/x2sin(x)2


= cos(x)/sin2(x)


= cot(x)cosec(x)


Integrating it gives -cosec(x) 


Definite Integral frm 0 to infiniity is cosec(0)+cosec(infinity) ---> undefined 

2 years ago
                                        integral x^2cosx/(xsinx)^2 dx
=integral cotx cosecx dx
=- cosecx +C

Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
4 months ago

Post Your Answer

More Questions On Integral Calculus

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
Integrate ∫sqroot(tanx) dx Reply soon....
 
 
Ans:Hello student, please find answer to your question
  img
Jitender Singh one month ago
The slope of the tangent to a curve y=f(x) at (x, f(x)) is 2x+1. If the curve passes through the point (1,2), then the area of the region bounded by the curve, the x-axis and the line x=1 is...
 
 
Ans: Hello Student, Please find answer to your question below Slope of the curve at any point x Integrate both sides It is passing through (1, 2) Area bounded by curve in the given region:
  img
Jitender Singh 18 days ago
integrate 1/ sincubex- coscubex
 
 
=
  img
Sher Mohammad 5 months ago
 
how u have given this ans plz rectify it dont post wrong ans plz
 
keshav kr 5 months ago
 
dear it is sin cube x not sin x cube and similarly in cos also
 
keshav kr 5 months ago
Prove that [cosx – sinx][cos2x – sin2x] = cosx – sin3x
 
 
Ans: Hello Student, Please find answer to your question below Hence Proved
  img
Jitender Singh 20 days ago
 
the value of cos6 sin24 cos72
 
laxman 19 days ago
 
wqwqwqwq
 
laxman 19 days ago
If the pth and qth terms of an AP be a and b respectively, show that the sum of the first (p+q) terms of the AP is (p+q)/2{a+b+(a-b/p-q)}
 
 
Hello Student, Now its obvious. Substitute the values to get the answer. Thanks & Regards Arun Kumar Btech, IIT Delhi Askiitians Faculty
  img
Arun Kumar one month ago
prove that the value of 5cosθ + 3cos(θ+π/3) + 3 lies between -4 and 10
 
 
5cosθ + 3cos(θ+π/3) + 3 = 5cosθ + 3(cosθcosπ/3 – sinθsinπ/3) + 3 = 5cosθ + 3*cosθ*1/2 – 3*sin θ*sqrt(3/2 ) + 3 = 13/2*cosθ – 3sqrt(3/2 )*sinθ + 3 The range of acosθ + b sinθ + c is c ± sqrt...
 
Y RAJYALAKSHMI 2 days ago
View all Questions »