Integral of cosec-1 x 


In above it is cosec inverse x.

2 years ago

Share

Answers : (1)

                                        

Dear Pankaj,


Take cosec^-1 x=sin^-1 1/x then see where do the function changes its value from one integer to another within the limits and then integrate.


Best Of luck


Cracking IIT just got more exciting,It s not just all about getting assistance from IITians, alongside Target Achievement and Rewards play an important role. ASKIITIANS has it all for you, wherein you get assistance only from IITians for your preparation and win by answering queries in the discussion forums. Reward points 5 + 15 for all those who upload their pic and download the ASKIITIANS Toolbar, just a simple  to download the toolbar….


So start the brain storming…. become a leader with Elite Expert League ASKIITIANS


Thanks


Aman Bansal


Askiitian Expert



2 years ago

Post Your Answer

More Questions On Integral Calculus

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
WHat is the integration of a x /b x?
 
 
Integral : (a/b)^x / log(a/b)Thanks Bharat BajajIIT Delhi askiitians faculty
  img
bharat bajaj one month ago
 
Hello Thanks & Regards Arun Kumar Btech, IIT Delhi Askiitians Faculty
  img
Arun Kumar one month ago
 
Thanks Bharat BajajIIT Delhi askiitians faculty
  img
bharat bajaj one month ago
Find the area of the region enclosed by the curve y = 1 1+x2 and it’s asymptote. PLEASE EXPLAIN THE ALL THE SUMS BY STEP BY STEP SIR
 
 
This curve approaches to y = 0 as x approaches infinity. Hence, y=0 is its asymptote. Hence, now find out the area under this curve. Area = 2 X Integral of y(Limits 0 to inf. ) A = 2 ....
  img
bharat bajaj 4 months ago
f(x)=1+2sin x+3cos ²x[0,2p÷3) find max value of function
 
 
f(x)=1+2sin x+3cos ²x f(x)=1+2sin x+ 3 (1 - sin 2 x) f(x) = -3sin 2 x + 2 sin x + 4 df(x)/dx = -6sinxcosx + 2cosx = 0 hence, sin x = 1/3 or cosx = 0 d/dx(df(x)/dx) = -3cos2x - 2sinx It is...
  img
bharat bajaj 5 months ago
 
f(x)= -3sin 2 x + 2sinx + 4 = -3(sin 2 x-2/3 sinx)+4 =-3(sinx-1/3)^2+3/9+4 =-3(sinx - 1/3)+13/3 now 0=<sin x<=1 when 0=<x=<2p/3 -1/3=<(sinx-1/3)=<2/3...
  img
Parvez ali 5 months ago
Period of [sinx]
 
 
Ans: Same pattern will repeat after this. Time period of f(x) Thanks & Regards Jitender Singh IIT Delhi askIITians Faculty
  img
Jitender Singh 25 days ago
If from a variable point ‘P’ on the line x-2y+1=0 pair of tangents are drawn to the parabola y 2 =8x then prove that the chord of contact passes through a fixed point, also find...
 
 
Let the point be (h,k) then h - 2k + 1 = 0 ----- (1) equation of chord of contact will be T = 0, i.e, yk = 8 (x + h)/2 yk = 4x + 4h ---- (2) Put value of h from equation (1) into equation...
  img
Pratik Tibrewal 6 months ago
Find the real values of the parameter ‘a’ for which atleast one complex number z =x+iy satisfies both the equality |z- ai|=a+4 and the inequality | z-2|
 
 
Hello Student, Please find the answer to your question below For these two to have atleast one solution, then both circles must intersect 1st circle intersect the x – axis at 1 &...
  img
Jitender Singh 6 days ago
View all Questions »