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manoj jangra Grade: 12
        

2x-[x]  .dx


limits from 0 to [x]

7 years ago

Answers : (1)

bibhash jha
15 Points
										

 


To solve this divide the integrals into o to 1 ,1 1to 2 ..... upto [x]-1 to [x]


 


so you get integrations of 2^(x-0) from 0 to 1 +2^(x-1) from 1 to 2 .... upto 2^(x-[x]+1) from [x-1]to [x]


 


each integral evaluates to 1/ln2 so we have [x] terms in our integral sum expression ..


 


therefore you get  ans=[x]/ln2

7 years ago
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