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Vanya Saxena Grade: Upto college level
        

Let sn=∑k=1 to n[n/(n2+kn+k2)] and Tn=∑k=0 to (n-1)  [n/(n2+nk+k2)] for n=1,2,3....... Then


A  Sn‹ pi/3√3                          C  Tn

B  Sn> pi/3√3                           D  Tn>pi/3√3

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Hi vanya


You can find Sn by summation of series using definite intigral as the limit of sum


sn=∑k=1 to n[n/(n2+kn+k2)]


sn=1/n∑k=1 to n [n2/(n2+kn+k2)]


sn=1/n∑k=1 to n [1/(1+k/n+(k/n)2)]


sn =∫1/(1+x+x2)dx   limit 0 to 1


   after solving


sn =pi/3√3





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 We are all IITians and here to help you in your IIT JEE preparation. All the best vanya
 
 

Regards,

Askiitians Experts

BAdiuddin




   



7 years ago
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