Free JEE ADV-13 Course
value of ∫dx/√3 sinx+cosx is equal to=? give the process of it also.plz reply soon!
Multiply and divide by 2.
I= dx/root(3) sinx+cosx then 2I= dx/(root(3)/2 *sinx + (cosx)/2 )
then root(3)/2=cos30 1/2 = sin 30
then root(3)sinx+ cosx becomes 2sin(30+x) . then the integration becomes integration of cosec(x+30) multiplied by 1/2. which equals [log(tan(x+30)/2))] . 1/2+constant. HOPE I HAVE NOT CONFUSED U!
(√3)i=(-cosx+sinx) + c
no complexity now convet into anythin u wantt