Forum  >> Integral Calculus  >> indefinite integral

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Title: indefinite integral
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Posted On: Sep 04, 2011 10:00 AM

value of ∫dx/√3  sinx+cosx is equal to=? give the process of it also.plz reply soon!

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basit ali
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Sep 04, 2011 11:06 AM

Multiply and divide by 2.

I= dx/root(3) sinx+cosx

then 2I= dx/(root(3)/2 *sinx + (cosx)/2 )

then root(3)/2=cos30 1/2 = sin 30

then root(3)sinx+ cosx becomes  2sin(30+x) .  then the integration becomes integration of cosec(x+30) multiplied by 1/2.

which equals  [log(tan(x+30)/2))] . 1/2+constant.

HOPE I HAVE NOT CONFUSED U!

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Mar 30, 2012 06:13 PM

(√3)i=∫(sinx+cosx)dx

(√3)i=(-cosx+sinx) + c

no complexity now convet into anythin u wantt

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