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integration between (-1to 3/2) of |x sin((pi)x)|=kp2.find the value of k? (where | | is the modulus function)
For x: -1<x<0 |x sin((pi)x)| is positive
For x: 0<x<1 |x sin((pi)x)| is positive
For x: 1<x<3/2 |x sin((pi)x)| is negative
so, its
integration from (-1 to 1) x sin((pi)x).dx - integration from (1 to 3/2) x sin((pi)x).dx
integral of x sin((pi)x).dx is -x.cos((pi)x)/Pi + sin((pi)x)/(Pi)2
so value is
1/Pi - 1/(Pi)2
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