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suchintan mondal Grade: 12
        

integration between  (-1to 3/2) of |x sin((pi)x)|=kp2.find the value of k? (where | | is the modulus function)

7 years ago

Answers : (1)

Ramesh V
70 Points
										

For x:   -1<x<0        |x sin((pi)x)| is positive


For x:   0<x<1          |x sin((pi)x)| is positive


For x:   1<x<3/2       |x sin((pi)x)| is negative


so, its


integration from (-1 to 1)  x sin((pi)x).dx  -   integration from (1 to 3/2)  x sin((pi)x).dx


integral of x sin((pi)x).dx  is       -x.cos((pi)x)/Pi  +  sin((pi)x)/(Pi)2


so value is


1/Pi -  1/(Pi)2


 





 

7 years ago
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