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Let for all n belonging to real number,n-2>=2ln n,then the minimum value of the area bound by the curve |y|+1/n<=e^ -|x| is 2 sq. unit. True or false
From n-2 >= 2*ln(n)
we can say n> 0 which also mean: n-1 > 0
Now from the curve |y|+1/n <= e-|x| or |y| <= e-|x| +1/n
Now the graph of e-|x| is symmetric about Y axis
for 1/n > 0 ;
CASE 1: lets take least value 1/n = 0
so, |y| <= e-|x|
For , |y| <= e-|x| the area bounded is 2*integral of e-|x| with limits from 0 to infininty
so area is 2 sq. units
CASE 1: lets take value 1/n more than 0
So so |y| <= e-|x| - 1/n
here e-|x| - 1/n becomes negative as shown in graph
but |y| is always positive which can never be less than a negative no.
so case 2 is not possible
hence area bounded is 2 sq. units and its TRUE
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