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MD ASIF IQUBAL Grade: 12
        integrate sin^8x.dx
8 years ago

Answers : (1)

AskiitianExpert Shine
10 Points
										

Hi


Split the sin8x dx into sin2x sin6 x dx, and mutiply the numerator and denominator by 3cosx,


Hence the expression becomes 3sin2x sin6x  cosx dx / 3cosx ..  now take sin3x = t and substitute in the expression. We made this substitution because on differentiating sin3x , we get 3sin2x cosx dx, hence we can directly substitute it in the expresssion.


After substitution we get, t2dt/3 (1-t2/3)1/2 . Again make a substitution of y2 = 1-t2/3 .


Try at all times , to somehow eliminate the denominator term, wen u get to that step, use the formulas specified for particular forms.

8 years ago
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