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aditya suman Grade: 12
        

[log(1+x)]/(1+x^2)


lower lim 0


upper lim 1

6 years ago

Answers : (2)

ABHISHEK SINGHAL
18 Points
										

PUT X=TANT


ASSUME FUNCTUION TO BE I AND THE LIMITS OF INTEGRATION WOULD BE 0 TO PIE/4 


USE F(A+B-X)=F(X) AND 1ST AND SECOND U WILL SURE GET ANS I,E (PIE/8)LN2

6 years ago
vikas askiitian expert
510 Points
										

I = [log(1+x)] dx / (1+x2)          lim 0 to 1


 


put log(1+x) = t


 


dx = (1+x)dt = etdt


 


I = [t] et d t /(1+(et - 1)2)        lim 0 to log2


 


I = [t] et dt /(1+(et-1)2)           lim 0 to 0.3


 


[t] , greatest integer t  value is equal to 0 for this interval ...


 


I = 0

6 years ago
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