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`        A car  was  moving with avelocity of 30 m/s. the driver braked and the car stopped after 2 seconds.assuming that the acceleration of the car was constant during the pressure period , find the acceleration and the distance travelled by the car between the time the driver pressed the brakes and the stopping time`
6 years ago

510 Points
```										initial velocity  = u = 30m/s
final velocity = v= 0
accleration = a
we have , v = u + at
0 = 30 + 2a
or      a = -30/2 = -15m/s2            (retardation)
now  , we have
v2  =  u2  +  2as
v=0 , u =30 , a=-15
0 = 302 + 2*(-15)s
s = 30m
retardation = -15m/s2   &  distance covered before stopping is 30m
```
6 years ago
419 Points
```										Dear Student
As acceleration is constant
Apply V=u+at
here final velocity V=0
a=-u/t = -30/2=-15 m/s2
-ve sign denotes deceleration (acceleration opposite to the direction of initial velocity)
now apply S=ut + at2/2
S=30*2 -15*22/2 = 60-30= 30m

All the best.
AKASH GOYAL

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6 years ago
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