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baha jaff Grade:
        

A car  was  moving with avelocity of 30 m/s. the driver braked and the car stopped after 2 seconds.assuming that the acceleration of the car was constant during the pressure period , find the acceleration and the distance travelled by the car between the time the driver pressed the brakes and the stopping time

6 years ago

Answers : (2)

vikas askiitian expert
510 Points
										

initial velocity  = u = 30m/s


final velocity = v= 0


accleration = a     


we have , v = u + at


               0 = 30 + 2a               


  or      a = -30/2 = -15m/s2            (retardation)


now  , we have 


            v2  =  u2  +  2as


 v=0 , u =30 , a=-15


        0 = 302 + 2*(-15)s


       s = 30m                 


retardation = -15m/s2   &  distance covered before stopping is 30m

6 years ago
AKASH GOYAL AskiitiansExpert-IITD
419 Points
										

Dear Student


As acceleration is constant


Apply V=u+at


here final velocity V=0


a=-u/t = -30/2=-15 m/s2


-ve sign denotes deceleration (acceleration opposite to the direction of initial velocity)


now apply S=ut + at2/2


S=30*2 -15*22/2 = 60-30= 30m


 


All the best.                                                           


AKASH GOYAL


AskiitiansExpert-IITD


 


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6 years ago
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