MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

Get extra R 320 off
USE CODE: MOB20

				   

Integrate:-\


x2sin2xdx

6 years ago

Share

Answers : (1)

										

 


Dear Aparna ,


 


sin2(x) = 1/2 - 1/2 cos(2x)


substitute value of sin2x from above in the integral and solve by parts.


 


Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.


All the best.


Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.


Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar  respectively : Click here to download the toolbar..


 


Askiitians Expert


Anil Pannikar


IIT Bombay

6 years ago

Post Your Answer

Other Related Questions on Integral Calculus

what is integration? and what is the real life applications of an integration?
 
 
Dear Sudharshan Integration is the one symboll used in solving problems . Integration is opposite to differentiation. It is usefull in mathematics, physics and chemistry
 
Prabhakar ch one year ago
 
DEAR SUDARSHAN, Integration is the act of bringing together smaller components into a single system that functions as one. Integration is used to compute such things as the areas and volumes...
 
naresh raju one year ago
 
dear sudarshan..... Integration is a way of adding slices to find the whole. Integration can be used to find areas, volumes, central points and many useful things. But it is easiest to start...
 
mohan one year ago
integral of sin with respect to x
 
 
Its −cosx(minus sign is also there).PLZ approve .
 
Nikhil Upadhyay one year ago
 
integral sinx = -cosx
 
sri tanish one year ago
 
∫sinx.dx=-cosx+c
 
Shantanu Singh one year ago
∫(1/sinx)dx
 
 
1/sinx =cosec x or integration of 1/x = ln |x|+c where c is arbitari constant so by using this formula integration of i/sinx is ln |sinx +c|
 
kalyan 7 months ago
 
sorry made a mistake currect answer is 1/sinx =cosec x integration of cosec(x) is ln|cosec x-cot x|+c where c is arbitari constant....
 
kalyan 7 months ago
 
1/sin(x)=cosec (x) the integration of cosec(x) is ln|cosec x-cot x|+c where cis an arbitrary constant
 
SREEKANTH 7 months ago
If alpha is a real root of the equation ax 2 +bx+c and beta is a real root of equation -ax 2 +bx+c. Show that there exists a root gama of the equation (a/2)x 2 +bx+c which lies between alpha...
 
 
 
Ajay 6 months ago
 
Small Mistake in last para posting again..............................................................................................................
 
Ajay 6 months ago
 
We have Similarly, So if P(x) = a/2 x 2 +bx +c, then and are off opposite sign and hence there must exist a root between the two numbers.
 
mycroft holmes 6 months ago
In the listed image can you tell me how beta*gamma = 2 ….. . . .. ??
 
 
The value of gamma is still not correct, either printing mistake or you gave me wrong value. The correct value of gamma is below
 
Ajay 5 months ago
 
Thankyou so much............................. …......................................................................!
 
Anshuman Mohanty 5 months ago
 
Yes sorry..... . . . .it is not so clear.. ok the values are beta = α + α^2 + α^4 and gamma = α^3 + α^5 + α^7
 
Anshuman Mohanty 5 months ago
if |z - i| Options: a*) 14 b) 2 c) 28 d) None of the above
 
 
If |z-i| = ?? PLs complete the question
  img
Nishant Vora one month ago
 
Got it! [z + 12 – 6 i ] can be rewritten as [ z – i + 12 – 5 i] => | z – i | and => |12 – 5 i | = sqrt ( 12^2 + 5^2) = 13......................(2) => | z + 12 – 6 i | => | z + 12 – 6 i |...
 
Divya one month ago
 
I tried posting the question several times, it kept cutting off the rest of the question. Here: If | z-1| Options: a*) 14 b) 2 c) 28 d) None of the above
 
Divya one month ago
View all Questions »

  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 3,000 off
USE CODE: MOB20

Get extra R 320 off
USE CODE: MOB20

More Questions On Integral Calculus

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details