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swetha iiit Grade: 12
        

evaluate integrand sin(3x)cos(4x)cos(7x)

6 years ago

Answers : (2)

jagdish singh singh
168 Points
										

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6 years ago
vikas askiitian expert
510 Points
										

I = sin3x.cos4x.cos7xdx


  =1/2 [sin3x(2cos4xcos7x)]dx                  (2cosacosb = cosa+b+ cosa-b )


  =1/2[sin3x(cos11x + cos3x)]dx


  =1/4[2sin3xcos11x +2sin3xcos3x]dx        (2sinacosb = sina+b + sina-b)


  =1/4[sin14x - sin8x + sin6x]dx


  =1/4 [-cos14x/14 + cos8x/8 - cos6x/6] + c


 

6 years ago
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