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Souradeep Majumder Grade: Upto college level
        


6 years ago

Answers : (1)

Askiitians_Expert Yagyadutt
askIITians Faculty
74 Points
										

Hello majumder


 


Let us assume x = I + f  where I is integral part and f is fractional part ..


intg ( 0 to I ) [x].dx  + intg ( I to I+f) [x].dx


 


I(I-1)/2   + I ( I+f - I)


 


= I(I-1)/2 + I . f    ans


 


Note : Intg ( o to n ) [x] .dx where n is integer = n(n-1)/2 ..so i have used it .


 


Also  intg ( I to I+f) [x] .dx  means x varies from I to I + f ...therefore [x] = I


----= intg ( I to I+f) .I.dx = I ( I+f - I ) = I.f  


 


Is it clear or not !


 


Yagya


askiitians_expert

6 years ago
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