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`        integration of (x+1)/sqrt(x^2-x+1)`
7 years ago

Sukhendra Reddy Rompally B.Tech Mining Machinery Engg, ISM Dhanbad
93 Points
```										Dear student,write the numerator as (2x-1)+3,then you can divide the integrand into 2 parts,1st one is a simple 1/root x form nd the second-write the denominator as root of (x-1/2)^2 + 3/4.i guess you can solve it from here.if you still have a problem,feel free to call me on 07209736303
```
7 years ago
510 Points
```										(x^2-x+1)=x^2-x+1/4+3/4
=(x-1/2)^2 + 3/4
integral(x+1)/sqrt(x^2-x+1)=x+1/sqrt{(x-1/2)^2 + 3/4}
now put x-1/2=t
dx=dt
integral(t+3/2)/sqrt(t^2+3/4)
= int{ t/sqrt(t^2+3/4)  + 3/4sqrt(t^2+3/4) }
= sqrt(t^2 +3/4)   + 3/4log{sqrt(t^2+3/4) +t} +c
=sqrt{ (x-1/2)^2 +3/4}   +   3/4 log{sqrt(x-1/2)^2 +x +1/4 } +c
```
7 years ago
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